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You toss a pair of dice. (a) Determine the number of possible pairs of outcomes. (Recall that there are six possible outcomes for each die.) (b) There are three even numbers on each die. How many outcomes are possible with even numbers appearing on each die? (c) Probability extension: What is the probability that both dice will show an even number? (Round your answer to two decimal places.)

Respuesta :

(a) When two dice are rolled, the total outcome we would have is have n(S) = (6 × 6) = 36 outcomes.

(b) The number of outcome gotten for even numbers, which is 3 per dice is n(S) =(3 × 3)= 9 outcomes.

(c) The probability that both dice will show an even number, is one over total even number outcomes.

Probability of even number=>

P(E)=1/9= 0.11

ogorwyne

A. We have two dice in this question. A die is known to be make up of 6 faces.

  • Therefore the number of faces for two dice = 6*6 = 36

B. Out of these two dice, one die has 3 odd numbers and three even numbers.

  • Therefore the number of even number outcomes for both dice = 3*3 = 9

C. The probability of having an even number

  • This is 1/9, remember 9 is the total number of even numbers = 0.1111

What is probability?

In mathematics or the field of statistics, probability is defined as the extent or the likelihood of something happening.

Read more on probability here:

https://brainly.com/question/24756209

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