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29-10-2019
Mathematics

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write an explict equation of how a computer at 2500$ depricates at the rate of 14% per year

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29-10-2019

Answer:

V(t) = 2500(0.86)^t where t = the year.

Step-by-step explanation:

Each year the value will be 100 - 14 = 86% ( - 0.86) of the previous year.

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