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Given : 11x – 6y = –1; x = 8


Prove: start fraction 89 over 6 end fraction = y


11x – 6y = –1; x = 8


88 – 6y = –1


–6y = –89


y = start fraction 89 over 6 end fraction



A. a. Given; b. Symmetric Property of Equality; c. Subtraction Property of Equality; d. Division Property of Equality; e. Reflexive Property of Equality

B. a. Given; b. Substitution Property; c. Subtraction Property of Equality; d. Division Property of Equality; e. Symmetric Property of Equality

C. a. Given; b. Substitution Property; c. Subtraction Property of Equality; d. Division Property of Equality; e. Reflexive Property of Equality

D. a. Given; b. Substitution Property; c. Subtraction Property of Equality; d. Addition Property of Equality; e. Symmetric Property of Equality

Respuesta :

Answer:

B. a. Given; b. Substitution Property; c. Subtraction Property of Equality; d. Division Property of Equality; e. Symmetric Property of Equality

Step-by-step explanation:

Given expression,

[tex]11x - 6y = -1; x = 8[/tex]

By substituting x = 8,

[tex]11(8) - 6y = -1[/tex]

[tex]88 - 6y =-1[/tex]

By subtraction property of equality,

[tex]-6y = -89[/tex]

Division property of equality,

[tex]y = \frac{89}{6}[/tex]

By symmetric property of equality,

[tex]\frac{89}{6} = y[/tex]

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