Answer with Step-by-step explanation:
Since we have given quadratic expressions in the form of
[tex]a^2-b^2[/tex]
which is equal to [tex](a+b)(a-b)[/tex]
a) z^2 + 4i = [tex](z-2i\sqrt{i})(z+2i\sqrt{i})[/tex]
b) z^2 + 4 = [tex](z-2i)(z+2i)[/tex]
c) z^2 − 4 = [tex](z-2)(z+2)[/tex]
d) z^2 − 4i = [tex](z+2\sqrt{i})(z-2\sqrt{i})[/tex]
Since a) and b) contains complex number so, it splits into complex linear factors.
