Respuesta :
Answer:
852.014 m
Explanation:
The speed of sound in air = 343 m/s = [tex]v_a[/tex]
The speed of sound in concrete = 3000 m/s = [tex]v_c[/tex]
The distance the sound traveled = s
Time between the sounds heard = 2.2 seconds
Time = Distance / Speed
Time taken by sound travel through air
[tex]\frac{s}{v_a}=\frac{s}{343}[/tex]
Time taken by sound travel through concrete
[tex]\frac{s}{v_c}=\frac{s}{3000}[/tex]
So,
[tex]\frac{s}{343}-\frac{s}{3000}=2.2\\\Rightarrow \frac{3000s-343s}{1029000}=2.2\\\Rightarrow \frac{2657s}{1029000}=2.2\\\Rightarrow s=\frac{1029000\times 2.2}{2657}\\\Rightarrow s=852.014\ m[/tex]
The impact occurs 852.014 m away from the person.
[tex]D= \frac{2.2}{0.002582} = 852 m[/tex]The impact that occurred when one travels in the air and the other in the concrete, and they are 2.2 s apart is [tex]852m[/tex] away .
What is sounds?
Sound can be regarded as a vibration that propagates through a transmission medium.
We were given the speed of sound for air as [tex]3000m/s[/tex]
Let the speed of sound in concrete be [tex](Vs) = 3000 m/s[/tex]
Let the speed of sound in air be[tex](Vi) = 343 m/s[/tex]
Since we know that Time is the ratio of distance per time = [tex]\frac{distance}{time}[/tex]
The we can substitute the values as:
Time for traveling in the [tex]air = D/343= 0.00291D[/tex] .....eqn(1)
Time for traveling in the [tex]concrete=D/3000= 0.000333 D[/tex].......eqn(2)
Then the difference between the two equation will gives us the impact that occur between them which is
[tex](0.00291D - 0.000333 D )= 2.2 secs[/tex]
[tex]0.002582 D= 2.2\\\\\\ D= \frac{2.2}{0.002582}[/tex]
Therefore, impact that occurred is 852 m away.
Learn more about sound at,;
https://brainly.com/question/13291061
