Answer:
The formula of nitrogen gaseous oxide is NO2.
Explanation:
Given data:
Mass of sample = 2.45 g
Volume = 1.34 L
Temperature = 28 °C (28+273.15 K = 301.15 k)
Pressure = 745 mmHg (745/ 760 = 0.9803 atm)
Formula of gaseous oxide of nitrogen =?
Solution:
Gaseous oxides of nitrogen are NO, N2O , NO2 , N2O4.
Formula:
PV = nRT
n = number of moles.
n = PV / RT
n =0.9803 atm × 1.34 L / 0.0821 atm. dm³. K⁻¹ . mol⁻¹ × 301.15 K
n = 1.314 atm . L / 24.72442 atm . dm.³mol⁻¹
n = 0.05315 mol
Now we will find the number of moles in 2.45 g of sample. Gaseous oxides of nitrogen are NO, N2O , NO2 , N2O4
First of all we will solve it for N2O.
number of moles = mass / molar mass
molar mass of N2O = 44 g/mol
number of moles = 2.45 g / 44 g/mol
number of moles = 0.056 mol
Now we will solve it for NO2.
molar mass of NO2 is 46 g/mol
number of moles = 2.45 g / 46 g/mol
number of moles = 0.0533 mol
Now we will solve it for NO.
molar mass of NO is 30 g/mol.
number of moles = 2.45 g / 30 g/mol
number of moles = 0.082 mol
Now we will solve it for N2O4.
molar mass of N2O4 is 92 g/mol.
number of moles = 2.45 g / 92 g/mol
number of moles = 0.027 mol
