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Tom has a mass of 67.1 kg and Sally has a mass of 58.6 kg. Tom and Sally are standing 32.3 m apart on a massless dance floor. Sally looks up and she sees Tom. She feels an attraction. If the attraction is gravitation, find its magnitude. Assume both can be replaced by point masses and that the gravitational constant is 6.67259 × 10−11 N · m2 /kg2 . Answer in units of N.

Respuesta :

Answer:[tex]F=25.14\times 10^{-11} N [/tex]

Explanation:

Given

mass of Tom[tex](m_t)=67.1 kg[/tex]

mass of sally[tex](m_s)=58.6 kg[/tex]

Distance between them(d)=32.3 m

Gravitational constant(G)[tex]=6.67\times 10^{-11} N.m^2/kg^2[/tex]

Gravitational attraction is given by

[tex]F=\frac{Gm_1m_2}{d^2}[/tex]

[tex]F=\frac{6.67\times 10^{-11}\times 67.1\times 58.6}{32.3^2}[/tex]

[tex]F=25.14\times 10^{-11} N [/tex]

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