Answer:
[tex]-3550.1 m/s^2[/tex]
Explanation:
The initial velocity of the ball is
u = +25.9 m/s (towards the wall)
while the final velocity of the ball is
v = -21.3157 m/s (away from the wall)
The time taken for the change in velocity to occur is
t = 0.0133 s
The acceleration can be calculated as the change in velocity divided by the time taken:
[tex]a=\frac{v-u}{t}[/tex]
Substituting the numbers, we find:
[tex]a=\frac{-21.3157-25.9}{0.0133}=-3550.1 m/s^2[/tex]
