Answer:
The energy of one photon of this light is 4.568 × 10∧ -19 J
Explanation:
Given data:
wavelength = 433.9 nm or 433.9 × 10∧-9 m
The value of speed of light is 3× 10∧8 m/s and plancks constant is 6.626 × 10∧-34 m²Kg/s
Formula:
E= hc/λ
E= energy of photon
h= plancks constant
c= speed of light
λ= wavelength of given light
Solution:
E= hc / λ
E = 6.626 × 10∧-34 m²Kg/s × 3× 10∧8 m/s / 433.9 × 10∧-9 m
E = 19.878 × 10∧-26 m²Kg/s² / 433.9 × 10∧-9 m
E = 0.04568 × 10∧ -17 J (Kg m²/s² =J)
E = 4.568 × 10∧ -19 J
Answer:
[tex]\large \boxed{4.578 \times 10^{-19} \text{ J}}[/tex]
Explanation:
The formula for the energy of a photon is
E = hc/λ
If λ = 433.9 nm, then
[tex]\begin{array}{rcl}E & = & \dfrac{6.626 \times 10^{-34} \text{ J$\cdot$s} \times 2.998 \times 10^{8}\text{ s}} {433.9 \times 10^{-9} \text{ m}}\\\\& = & 4.578 \times 10^{-19} \text{ J}\\\end{array}\\\text{The energy of one photon is $\large \boxed{\mathbf{4.578 \times 10^{-19}} \textbf{ J}}$}[/tex]
