Answer:
6.0 L
Explanation:
For this question, we can use
P1×V1= P2 × V2
where
P1 (initial pressure)= 0.2 kPa
V1 (initial volume)= 15L
P2 (final pressure)= 0.5 kPa
V2(final volume)= ?
Since we are trying to find final volume, we can rearrange the equation to make V2 the subject.
V2= (P1 × V1)/ P2
V2= (0.2 ×15)/0.5
V2 =6 L
