Answer:
R = 668.19 ft
Explanation:
given,
speed of the ball thrown by the pitcher = 100 mph
to travel maximum distance θ = 45°
distance traveled by the ball = ?
using formula
1 mph = 0.44704 m/s
100 mph = 44.704 m/s
[tex]R = \dfrac{u^2sin2\theta}{g}[/tex]
[tex]R = \dfrac{44.704^2sin2\times 45}{9.81}[/tex]
R = 203.71 m
1 m = 3.28 ft
R = 203.71 × 3.28
R = 668.19 ft
hence, ball will go at a distance of 668.19 ft when pitcher throw it at 100 mph.
