Answer:
The answer to your question is: KOH
Explanation:
Formula
Molarity = # of moles / volume
Process
a. No right answer.
b. 121.45 g of KOH in 75.0 mL
MW KOH = 56 g
56 g --------------------- 1 mol
121.45 g ----------------- x
x = (121.45 x 1) / 56
x = 2.17 mol
M = 2.17 / 0.075
M = 29
c. 23.49 g of NH4OH in 125.0 mL
MW NH4OH = 35 g
35 g -------------------- 1 mol
23.49 g --------------------- x
x = (23.49 x 1) / 35 = 0.67 mol
M = 0.67 / 0.125
M = 5.36
d. 217.5 g of LiNO3 in 2.00 L
MW LiNO3 = 69 g
69 g ---------------------- 1 mol
217.5 g ---------------------- x
x = (217.5 x 1) / 69 = 3.15 mol
M = 3.15 / 2
M = 1.6
e. 15.25 g of Pb(C2H3O2)2 in 65.0 mL
MW Pb(C2H3O2) = 266 g
266 g ------------------ 1 mol
15.25g ................... x
x = (15.25 x 1) / 266 = 0.06 mol
M = 0.06 / 0.065
M = 0.92
