A researcher reports that the time (in minutes) it takes children who are "picky eaters" to finish their vegetables is negatively skewed, with children finishing their vegetables in 4.2±1.0 (M±SD) minutes. Based on Chebyshev's theorem, we can conclude that68% of children finished their vegetables in 3.2 to 5.2 minutes.50% of children finished their vegetables in at least 3.2 minutes.99.7% of children finished their vegetables in 2.2 to 6.2 minutes.At least 89% of children finished their vegetables in 1.2 to 7.2 minutes.

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ChiKesselman ChiKesselman · Answer 1 · 2019-09-30T09:02:34+02:00

Answer:

Option d) Chebyshev's rule

Step-by-step explanation:

The Chebyshev's rule state that for a data that is not distributed normally,

atleast [tex](1 - \frac{1}{k^2})\% \text{ of data lies within the interval}~(Mean \pm (k)Standard ~Deviation)[/tex].

Here, k cannot be 1 and is always greater than 2.

For k = 2,

[tex](1 - \frac{1}{4})\times 100\% = 75\%[/tex] of data lies within the range of [tex](\mu \pm 2\sigma)[/tex]

Atleast 75% of children finished their vegetables in [tex](\mu \pm 2\sigma) = (4.2 \pm (2)1.0) = (2.2,6.2)[/tex]

For k = 3,

[tex](1 - \frac{1}{9})\times 100\% = 88.912\%[/tex] of data lies within the range of [tex](\mu \pm 3\sigma)[/tex]

Atleast 89% of children finished their vegetables in [tex](\mu \pm 3\sigma) = (4.2 \pm (3)1.0) = (1.2,7.2)[/tex]

Thus, option d) is correct.