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A 500-kg object is accelerating to the right at 10 cm/s2. What is the magnitude of the rightward net force acting on it (in Newtons)?

Respuesta :

Answer:

F = 50 N

Explanation:

As we know by Newton's II law

{tex]F = ma[/tex]

force is product of mass and acceleration

so we will have

[tex]m = 500 kg[/tex]

[tex]a = 10 cm/s^2[/tex]

[tex]a = 0.10 m/s^2[/tex]

now we have

[tex]F = 500 \times 0.10 [/tex]

[tex]F = 50 N[/tex]

asuwafohjames

The magnitude of the rightward net force acting on the object is 50 N.

What is force?

Force can be defined as the product of mass and acceleration.

To calculate the magnitude of the rightward net force, we use the formula below.

Formula:

  • F = ma............. Equation 1

Where:

  • F = Force on the object
  • m = mass of the object
  • a = acceleration due to gravity

From the question,

Given:

  • m = 500 kg
  • a = 10 cm/s² = 0.1 m/s²

Substitute these values into equation 1

  • F = 500(0.1)
  • F = 50 N

Hence, The magnitude of the rightward net force acting on the object is 50 N.

Learn more about force here: https://brainly.com/question/13370981

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