Respuesta :
Answer:
There is support for the firm's claim.
Step-by-step explanation:
We have to test the null hypotesis
[tex]H_{0}: \mu=13460[/tex]
The significance level is 0.01 (an area of 0.005 on both sides of the normal distribution curve). The interval that is defined by this significance levels are z1=-2.576 and z2=2.576.
We have to compute the probability value z
[tex]z=\frac{M-\mu}{\sigma_{n}/\sqrt{N}} =\frac{12781-13460}{1760/\sqrt{50}} =\frac{-679}{1760*7.07} =\frac{-679}{12445}= -0.0545[/tex]
Since this value of z=-0.545 lies inside the interval [-2.576,2.576], we can not reject the null hypotesis. The value of the sample mean (M=12781) was not significantly different from the mean of the population the firm claims (μ=13460).
There is support for the firm's claim.
