Explanation:
Given
launch angle[tex]=32^{\circ}[/tex]
ball lands exactly 224 m
Range of projectile =224 m
[tex]Range =\frac{u^2sin2\theta }{g}[/tex]
[tex]224=\frac{u^2sin64}{9.8}[/tex]
[tex]u^2sin64=224\times 9.8=2195.2[/tex]
[tex]u^2=2442.383[/tex]
u=49.42 m/s
(b)Maximum height reached
[tex]H_{max}=\frac{u^2sin^2\theta }{2g}[/tex]
[tex]H_{max}=\frac{49.42^2\times sin^{2}32}{2\cdot 9.8}[/tex]
[tex]H_{max}=34.99 m\approx 35 m[/tex]
