002 10.0 points
A tennis ball with a speed of 10.1 m/s is
moving perpendicular to a wall. After striking
the wall, the ball rebounds in the opposite
direction with a speed of 8.3426 m/s.
If the ball is in contact with the wall for
0.00905 s, what is the average acceleration of
the ball while it is in contact with the wall?
Take “toward the wall” to be the positive
direction.
Answer in units of m/s2.
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I don’t understand pleaseee help!

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MathPhys MathPhys · Answer 1 · 2019-09-26T03:43:53+02:00

Answer:

-2040 m/s²

Explanation:

Taking toward the wall to be positive, the initial velocity is 10.1 m/s and the final velocity is -8.3426 m/s.

Average acceleration is the change in velocity over change in time.

a = Δv / Δt

a = (-8.3426 m/s − 10.1 m/s) / 0.00905 s

a = -2040 m/s²

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