Respuesta :
Answer:
f(2)=0
f(-4)=24
Step-by-step explanation:
We are given
f(n)=n^2-2n
We are asked which of the following are true?
f(2)=0
f(1)=3
f(-4)=24
f(5)=35
f(-2)=0
Let's start with f(2)=0.
f(2)=2^2-2(2)
f(2)=4-4
f(2)=0
So f(2)=0 is true.
Moving on to f(1)=3.
f(1)=1^2-2(1)
f(1)=1-2
f(1)=-1
So f(1)=3 is false.
Now for f(-4)=24.
f(-4)=(-4)^2-2(-4)
f(-4)=16+8
f(-4)=24
So f(-4)=24 is true.
f(5)=35?
f(5)=5^2-2(5)
f(5)=25-10
f(5)=15
So f(5)=35 is false.
Finally f(-2)=0.
f(-2)=(-2)^2-2(-2)
f(-2)=4+4
f(-2)=8
So f(-2)=0 is false.
Answer:
The correct option are,
f(2) = 0, and f(-4) = 24
Step-by-step explanation:
Given function,
[tex]f(n) = n^2 - 2n[/tex]
By substituting n = 2,
[tex]f(2) = 2^2 - 2(2) = 4 - 4 = 0[/tex]
By substituting n = 1,
[tex]f(1) = 1^2 - 2(1) = 1 - 2 = -1[/tex]
By substituting n = -4,
[tex]f(-4) = (-4)^2 - 2(-4) = 16 + 8 = 24[/tex]
By substituting n = 5,
[tex]f(5) = (5)^2 - 2(5) = 25 - 10 = 15[/tex]
By substituting n = -2,
[tex]f(-2) = (-2)^2 - 2(-2) = 4 + 4= 8[/tex]
