Answer:
Explanation:
Time dilation formula is as follows
[tex]T_1=\frac{T}{\sqrt{1-\frac{v^2}{c^2} } }[/tex]
T₁ is time observed by stationary observer and T is time recorded by moving clock.
Given T = 1.02 and
T₁ = 3.84 X10⁸ / v [ Let v be velocity of spaceship as observed by observer on earth ]
Putting these values in the time dilation formula
3.84 x 10⁸ / v = \frac{1.02}{\sqrt{1-\frac{v^2}{9\times10^{16}} } }[/tex]
v = 2.345 x 10⁸ ms⁻¹
