Answer:
E=1.50\times 10^{-18}J
Explanation:
Energy of the one dimensional infinite well,
[tex]E=\frac{n^{2}h^{2} }{8mL^{2} }[/tex]
Given that, [tex]L=200 pm\\L=200\times 10^{-12}m[/tex]
For the ground state n=1,
Therefore energy is,
[tex]E=\frac{(6.626\times 10^{-34})^{2}}{8(9.1\times 10^{-31})(200\times 10^{-12}) ^{2} }\\E=1.50\times 10^{-18}J[/tex]
