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What is the grating separation (d) that corresponds to a source of wavelength 530.5 nm that produces a line at 44.2°? Calculate this value in nm using m=1.

Respuesta :

Answer:

761 nm

Explanation:

We have given the wavelength of source [tex]\lambda =530.5nm=530.5\times 10^{-9}m[/tex]

Angle [tex]\Theta =44.2^{\circ}[/tex]

In question it is said that use m= 1

We have to find grating separation

According to law of diffraction

[tex]dsin\Theta =m\lambda[/tex]

[tex]dsin44.2 =1\times 530.5\times 10^{-9}[/tex]

[tex]d=761nm[/tex]

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