Explanation:
It is given that,
Focal length of the concave mirror, f = -13.5 cm
Image distance, v = -37.5 cm (in front of mirror)
Let u is the object distance. It can be calculated using the mirror's formula as :
[tex]\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}[/tex]
[tex]\dfrac{1}{u}=\dfrac{1}{f}-\dfrac{1}{v}[/tex]
[tex]\dfrac{1}{u}=\dfrac{1}{(-13.5)}-\dfrac{1}{(-37.5)}[/tex]
u = -21.09 cm
The magnification of the mirror is given by :
[tex]m=\dfrac{-v}{u}[/tex]
[tex]m=\dfrac{-(-37.5)}{(-21.09)}[/tex]
m = -1.77
So, the magnification produced by the mirror is (-1.77). Hence, this is the required solution.
