Answer:
power 1.35 mw
ANGLE IS 33.27 degree
Explanation:
from Malus law we have following relation
[tex]I = I_0 cos^2\theta[/tex]
we know that
power = intensity * area
[tex]A*I_0 cos^2\theta = I*A[/tex]
[tex]I = I_0 cos^2\theta[/tex][tex]= 5.4*10^{-3} cos^2{60}[/tex]
= 0.0054*0.25
= 1.35 mw
2
[tex]I = I_o*cos^2(\theta)[/tex]
[tex]\theta = cos^{-1}(\sqrt{(\frac{I}{I_o})}[/tex]
= [tex]cos^{-1}(\sqrt{(0.70))}[/tex]
[tex]= cos^{-1}(0.836)[/tex]
= 33.27 degrees
