Answer:
209.66 m
Explanation:
Given:
Original length of the spaceship, L = 481 m
Speed of the spaceship, v = 2.70 × 10⁸ m/s
Now,
using the concept of length contraction, we have
[tex]L=\frac{L'}{\sqrt{1-\frac{v^2}{c^2}}}[/tex]
where,
L' is the observed length
c is the speed of the light
Thus,
on substituting the respective values, we get
[tex]481=\frac{L'}{\sqrt{1-\frac{(2.70\times10^8)^2}{(3\times10^8)^2}}}[/tex]
or
L' = 209.66 m
