Answer:
2.71 V
Explanation:
Usually in the cell notation, the left side shows oxidation. So,
Oxidation half reaction:
[tex]Mg_{(s)}\rightarrow Mg^{2+}_{(aq)}+2e^-[/tex] [tex]E^o_{ox}=-E^o_{red}=-(-2.37\ V)=2.37\ V[/tex]
Reduction half reaction:
[tex]Cu^{2+}_{(aq)}+2e^-\rightarrow Cu_{(s)}[/tex] [tex]E^o_{red}=0.34\ V[/tex]
Overall reaction:
[tex]Mg_{(s)}+Cu^{2+}_{(aq)}\rightarrow Mg^{2+}_{(aq)}+Cu_{(s)}[/tex]
[tex]E^o_{cell}=E^o_{ox}+E^o_{red}= (2.37+0.34)\ V=2.71\ V[/tex]
