Answer:
4.4×10⁻⁷ Coulomb
Explanation:
V = Voltage = 5.8 kV
d = Potential distance = 2.8 mm = 0.0028 m
A = Area = 0.3×0.08 = 0.024 m²
ε₀ = permittivity constant in a Vacuum= 8.85×10⁻¹² F/m
[tex]\frac{Q}{V}=\frac{A\epsilon_0}{d}\\\Rightarrow \Q=V\frac{A\epsilon_0}{d}\\\Rightarrow Q=5.8\times 10^3\frac{0.024\times 8.85\times 10^{-12}}{0.0028}\\\Rightarrow Q=4.4\times 10^{-7}\ C[/tex]
Magnitude of charge transferred between a carpet and a shoe is 4.4×10⁻⁷ Coulomb.
