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A garden hose discharges water at the rate of 15 m/s. If the nozzle is held at ground level and directed θ = 30° from the ground, determine the maximum height reached by the water and the horizontal distance from the nozzle to where the water strikes the ground.

Respuesta :

Answer:2.87m ,19.88 m

Explanation:

Given

water velocity (V)=15 m/s

nozzle angle [tex]=30 ^{\circ}[/tex]

it is similar to projectile motion

and maximum height is given by

[tex]H=\frac{v^2sin^2\theta }{2g}[/tex]

[tex]H=\frac{15^2sin^2(30)}{2\times 9.81}[/tex]

[tex]H=\frac{225\times \frac{1}{4}}{2\times 9.81}[/tex]

H=2.87 m

Horizontal Distance [tex]=\frac{v^2sin2\theta }{g}[/tex]

[tex]H=\frac{15^2sin(60)}{9.81}[/tex]

H=19.88 m

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