Answer:
- 16.72° C
Explanation:
L = 36 m
T1 = 18° C
Let it is 3 cm shorter at T2.
ΔL = 3 cm = 0.03 m
ΔT = T1 - T2
coefficient of linear expansion for Aluminium, ∝ = 24 x 10^-6 / °C
Use the formula for the thermal expansion
[tex]\Delta L =L\times\alpha \times\Delta T[/tex]
[tex]0.03 =36\times\24\times10^{-6}\Delta T[/tex]
ΔT = 34.72
T1 - T2 = 34.72
T2 = T1 - 34.72 = 18 - 34.72 = - 16.72° C
