Respuesta :

Answer:

A

Step-by-step explanation:

p³ - 125q³ ← is a difference of cubes and factors in general as

a³ - b³ = (a - b)(a² + ab + b³)

here a = p and b = 5q, hence

p³ - (5q)³

= (p - 5q)(p² + ( 5q)p + (- 5q)² )

= (p - 5q)(p² + 5pq + 25q²) → A

Answer:

A.

Step-by-step explanation:

The given expression is

[tex]p^{3}-125q^{3}[/tex]

This is the difference of two perfect cubes, which can be factored using the following formula

[tex]a^{3} -b^{3} =(a-b)(a^{2}+ab+b^{2} )[/tex]

Where [tex]a=p[/tex] and [tex]b=5q[/tex], because the cubic root of 125 is 5.

[tex]p^{3}-125q^{3}=(p-5q)(p^{2}+(p)(5q)+(5q)^{2} )\\p^{3}-125q^{3}=(p-5q)(p^{2}+5pq+25q^{2} )[/tex]

Therefore, the right answer is A, because it shows the correct factored form of the given difference.