Answer:1207.811 KPa
Explanation:
Given
Nozzle and hose are at same level thus
[tex]h_1=h_2[/tex]
Applying Bernoulli's equation
[tex]P_1+\frac{1}{2}\rho v_1^2+\rho gh_1=P_2+\frac{1}{2}\rho v_2^2+\rho gh_2[/tex]
thus
[tex]P_1-P_2=\frac{1}{2}\cdot rho\left ( v_2^2-v_1^2\right )[/tex]
Also discharge (Q)=AV
[tex]v=\frac{Q}{A}[/tex]
[tex]P_1-P_2=\frac{1}{2}\cdot rho\left ( \frac{Q^2}{A_2^2}-\frac{Q^2}{A_1^2}\right )[/tex]
[tex]P_1-P_2=\frac{1}{2}\cdot rho \left ( 49.729^2-7.573^2\right )[/tex]
[tex]P_1-P_2=1207.811 KPa[/tex]
