The probability that an even number in the first roll or that the number 1 will be in the second roll will be 1/12.
Its basic premise is that something will almost certainly happen. The percentage of favorable events to the total number of occurrences.
The faces of a fair cube are numbered 1 through 6; the probability of rolling any number from 1 through 6 is equally likely.
If the cube is rolled twice.
Then the probability that an even number will appear on the top face in the first roll or that the number 1 will appear on the top face in the second roll will be
Total event = 6 × 6 = 36
Favorable event = 3 {(2, 1), (4, 1), (6, 1)}
Then we have
P = 3/36
P = 1/12
More about the probability link is given below.
https://brainly.com/question/795909
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