Answer:
64.85 m
Explanation:
a)
μ = Coefficient of friction between road and tire on rainy day = 0.107
g = acceleration due to gravity = 9.8 m/s²
a = acceleration experienced by car due to friction = - μg = - (0.107) (9.8) = - 1.05 m/s²
v₀ = initial velocity of the car = 42 km/h = 11.67 m/s
v = final speed of the car = 0 m/s
d = minimum distance traveled before stopping
Using the equation
v² = v₀² + 2 a d
0² = 11.67² + 2 (- 1.05) d
d = 64.85 m
