Answer:
Δ S = 2.51 × 10²³ J/K
Explanation:
change of entropy formula
[tex]\Delta S = \dfrac{3}{2}Nln\dfrac{E_x}{E_n}[/tex]
N = 6.02 × 10²³ atoms
Initial thermal energy = Eₙ = 75 J
Final thermal energy,
Eₓ = 75 J + 22 J
Eₓ = 97 J
[tex]\Delta S = \dfrac{3}{2}Nln\dfrac{E_x}{E_n}[/tex]
[tex]\Delta S = \dfrac{3}{2}\times 6.02\times 10^{23} ln\dfrac{97}{75}[/tex]
Δ S = 2.51 × 10²³ J/K
