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There are 10 kids on the math team. Two kids will be selected from the team to compete in the state competition. How many ways are there to select the 2 competitors?

Respuesta :

Answer:

45 ways

Step-by-step explanation:

Total number of kids = 10

We have to select the 2 kids

So the number ways to select two kids [tex]^{10}C_2[/tex]

We know that [tex]^{n}C_r=\frac{n!}{r!(n-r)!}[/tex]

So [tex]^{10}C_2=\frac{10!}{2!(10-2)!}=\frac{10!}{2!\times 8!}=\frac{10\times 9\times 8!}{2\times 8!}=45[/tex]

So there are 45 ways to select 2 competitors

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