The nonreflective coating on a camera lens with an index of refraction of 1.23 is designed to minimize the reflection of 544-nm light. If the lens glass has an index of refraction of 1.56, what is the minimum thickness of the coating that will accomplish this task?

Respuesta :

Answer:

Thickness = 110.57 nm

Explanation:

Given that:

The refractive index of the lens = 1.56

The refractive index of the non reflecting coating = 1.23

The wavelength of the light = 544 nm

The thickness can be calculated by using the formula shown below as:

[tex]Thickness=\frac {\lambda}{4\times n}[/tex]

Where, n is the refractive index of the non reflecting coating = 1.23

[tex]{\lambda}[/tex] is the wavelength

So, thickness is:

[tex]Thickness=\frac {544\ nm}{4\times 1.23}[/tex]

Thickness = 110.57 nm