Answer: 25.30
Step-by-step explanation:
Given : Sample size of both samples : n= 5
A pooled variance : [tex]S_p=40[/tex]
The formula to find the standard error for the sample mean difference is given by :-
[tex]S.E.=S_p\sqrt{\dfrac{1}{n_1}+\dfrac{1}{n_2}}\\\\\Rightarrow\ S.E.=(40)\sqrt{\dfrac{1}{5}+\dfrac{1}{5}}\\\\\Rightarrow\ S.E.=(40)\sqrt{\dfrac{2}{5}}=25.2982212813\approx25.30[/tex]
Therefore, the estimated standard error for the sample mean difference is 25.30
