What are the values of the coefficients and constant term of 0=4-7x^2+x in standard form?

Question

contestada

Respuesta :

carlosego carlosego · Answer 1 · 2019-08-26T22:31:11+02:00

For this case we have that by definition, a quadratic equation is of the form:

[tex]ax ^ 2 + bx + c = 0[/tex]

Where:

[tex]ax ^ 2[/tex]: It is the quadratic term

bx: It is the linear term

c: It is the independent term

So, if we have the following expression:

[tex]0 = 4-7x ^ 2 + x[/tex]

We rearrange:

[tex]-7x ^ 2 + x + 4 = 0[/tex]

We have to:

-7: It is the quadratic coefficient

1: It is the linear coefficient

4: It is the independent term

ANswer:

-7: It is the quadratic coefficient

1: It is the linear coefficient

4: It is the independent term

luisejr77 luisejr77 · Answer 2 · 2019-08-26T22:34:50+02:00

Answer:

[tex]a=-7\\b=1\\c=4[/tex]

Step-by-step explanation:

The standard form of a quadratic equation has the following formula:

[tex]ax^2 +bx+c=0[/tex]

Where a and b are the coefficients that accompany the term x² and x and c is the constant term.

In this case we have the following equation:

[tex]0=4-7x^2+x[/tex]

We can rewrite the equation in the following way

[tex]-7x^2+x+4=0[/tex]

Then you can see that the values for the coefficients and constant term are:

[tex]a=-7\\b=1\\c=4[/tex]