Answer:[tex]\frac{77}{96}[/tex]
Step-by-step explanation:
Given
weight of 8 Type A widget is equal to weight of 3 type B widgets
i.e. 8A=3B (Let's say)
[tex]A=\frac{3}{8}B[/tex]
Also
Weight of 5 Type B widgets is equal to the weight of 7 type C widgets
i.e.
5B=7C
[tex]C=\frac{5}{7}B[/tex]
ratio of total weight of 1 type A widget and 1 type B widget, to the total weight of 1 type B widget and 1 type C widget
[tex]\frac{A+B}{B+C}=\frac{\frac{3}{8}B+B}{B+\frac{5}{7}}[/tex]
[tex]=\frac{11\times 7}{8\times 12}=\frac{77}{96}[/tex]
