Answer:
[tex]4x^3-x^2-5x[/tex]
Step-by-step explanation:
Let [tex]a,b,c,d\in \mathbb R[/tex], then the distributive property states that:
[tex]a(b+c+d+e)=ab+ac+ad+ae[/tex]
The given expression is [tex]x(2x+4x^2-5-3x)[/tex]
We apply the distributive property to get:
[tex]2x*x+4x^2*x-5*x-3x*x)[/tex]
[tex]2x^2+4x^3-5x-3x^2[/tex]
Combine like terms
[tex]4x^3-5x-3x^2+2x^2[/tex]
Simplify:
[tex]4x^3-5x-x^2[/tex]
Write in descending powers of x.
[tex]4x^3-x^2-5x[/tex]....This is the standard form
