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An object is launched from a platform.
Its height (in meters), x seconds after the launch, is modeled by

h(x)=-5(x+1)(x-9)

What is the height of the object at the time of launch?

_________ meters

Please answer as soon as possible please!

Respuesta :

yungsherman

Answer:

45 meters

Step-by-step explanation:

If x represents the seconds after the launch, then the time of launch is when x=0 so you just need to solve for h(0)

h(0) = -5(1)(-9)

h(0) = 45

Answer:

45 m

Step-by-step explanation:

At the time of launch, the time x = 0

Substitute x = 0 into h(x)

h(0) = - 5 (0 + 1)(0 - 9) = - 5(1)(- 9) = - 5 × - 9 = 45

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