Answer:
15.36 moles of carbon dioxide are produced when 5.12 mol of propane gas is burned in excess oxygen
Explanation:
The Balanced Chemical equation is :
[tex]C_3 H_8 (g) + 5O_2 (g) > 3CO_2 (g) + 4H_2 O(l)[/tex]
Mole ratio of [tex]C_3 H_8:CO_2[/tex] is 1 : 3
That is, 1 mole of propane gas produces 3 moles of carbon dioxide gas.
Using mole ratio we can solve this
[tex]5.12mol C_3 H_8 \times \frac {(3mol CO_2)}{(1mol C_3 H_8 )}[/tex]
[tex]=15.36 mol CO_2[/tex] is produced.
(Answer)
Please note :
To convert moles to mass, we multiply by molar mass
To convert mass to moles, we divide by molar mass
Molar mass is the mass of 1 mole of the substance
For example molar mass of [tex]CO_2[/tex] is
[tex](12.0+2\times16)=44 g/mol[/tex]
(we just add the atomic mass of the atoms to get the molar mass of the substance)
