Bob owns a watch repair shop. have the lowest cost? operating his shop s given by C·2x2 He has found that the cost o 216x + 1 1 243 where C s the cost in dolars, and x s the number of watches repaired How many watches must he re r How many watches must he repair to have the lowest cost?

Respuesta :

Answer:

The number of watches must he repair to have the lowest cost is 54.

Step-by-step explanation:

The cost of operating Bob's shop is given by

[tex]C(x)=2x^2-216x+11243[/tex]

Differentiate the given function with respect to x.

[tex]C'(x)=2(2x)-216(1)+(0)[/tex]

[tex]C'(x)=4x-216[/tex]             ... (1)

Equate C'(x) equal to 0, to find the critical point.

[tex]0=4x-216[/tex]

[tex]216=4x[/tex]

Divide both sides by 4.

[tex]\frac{216}{4}=x[/tex]

[tex]54=x[/tex]

Differentiate C'(x) with respect to x.

[tex]C''(x)=4[/tex]

C''(x)>0, it means the cost of operating is minimum at x=54.

Therefore the number of watches must he repair to have the lowest cost is 54.