Respuesta :
Answer: 0.407 grams of Zn has been consumed.
Explanation: Zn reacts with hydrochloric acid to form hydrogen gas. The balanced equation is given below:
[tex]Zn(s)+2HCl(aq)\rightarrow ZnCl_2(aq)+H_2(g)[/tex]
Barometric pressure is given as 739 torr which is the sum of partial pressures of hydrogen gas and water vapors. Water vapor pressure is given as 22.38 torr.
So, partial pressure of dry hydrogen gas = 739 torr - 22.38 torr = 716.62 torr
Convert the pressure from torr to atm.
760 torr = 1 atm
so, [tex]716.62torr(\frac{1atm}{760torr})[/tex]
= 0.943 atm
Temperature is given as 24 degree C. In kelvin it will be 24+273 = 297 K
Volume of the gas is given as 161 mL that is 0.161 L.
From this information we can calculate the moles of hydrogen gas formed using ideal gas law equation.
PV = nRT
[tex]n=\frac{PV}{RT}[/tex]
R is universal gas law constant and its value is 0.0821 atm.L/(mol.K).
Let's plug in the values in the equation to calculate moles(n) of the gas.
[tex]n=\frac{0.943atm*0.161L}{0.0821atm*L*mol^-^1*K^-^1*297K}[/tex]
n = 0.00623 moles
From the balanced equation, there is 1:1 mol ratio between zinc and hydrogen gas. So, the moles of Zn used will also be 0.00623.
Multiply the moles by molar mass to convert into grams. Molar mass of Zn is 65.38 gram per mol.
[tex]0.00623mol(\frac{65.38g}{1mol})[/tex]
= 0.407 gram
So, 0.407 grams of Zn have been consumed.
The mass of Zinc, Zn that has been consumed is 0.403 g
How to determine the mole of hydrogen collected
- Volume (V) = 161 mL = 161 / 1000 = 0.161 L
- Temperature (T) = 24 ˚C = 24 + 273 = 297 K
- Pressure (P) = 739 – 22.38 = 716.62 torr = 716.62 / 760 = 0.943 atm
- Gas constant (R) = 0.0821 atm.L/Kmol
- Number of mole (n) =?
The number of mole can be obtained by using the ideal gas equation as illustrated below:
n = PV / RT
n = (0.943 × 0.161) / (0.0821 × 297)
n = 0.0062 mole
How to determine the mass of Zn consumed
Balanced equation
Zn + 2HCl —> ZnCl₂ + H₂
From the balanced equation above,
1 mole of H₂ was produced from 1 mole of Zn.
Therefore,
0.0062 mole of H₂ will also be produced from 0.0062 mole of Zn
Thus, the mass of Zn consumed can be obtained as
- Mole of Zn = 0.0062 mole
- Molar mass of Zn = 65 g/mol
- Mass of Zn =?
Mass = mole × molar mass
Mass of Zn = 0.0062 × 65
Mass of Zn = 0.403 g
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