Respuesta :
Answer:
11, 12, 13
Step-by-step explanation:
x is the first number
(x + 1) is the second number
(x + 2) is the third number
x + x+1 + x+2 = 36
3x + 3 = 36
3x = 36 - 3
3x = 33
x = 11 ← the first number
the second number = x + 1 = 11 + 1 = 12
the third number = x + 2 = 11 + 2 = 13
[tex]\huge{\boxed{11}}\ \ \huge{\boxed{12}}\ \ \huge{\boxed{13}}[/tex]
First, represent the numbers with variables. [tex]x[/tex] is the first number. [tex]x+1[/tex] is the second number, since they are consecutive. [tex]x+2[/tex] is the third and final number.
Make a statement. [tex]x+x+1+x+2=36[/tex]
Combine the variables. [tex]3x+1+2=36[/tex]
Combine the constants. [tex]3x+3=36[/tex]
Isolate the variable by subtracting [tex]3[/tex] on each side. [tex]3x=33[/tex]
Finish isolating the variable by dividing both sides by [tex]3[/tex]. [tex]x=11[/tex]
This means the first number is [tex]\boxed{11}[/tex]. Since the three numbers are consecutive, the other two numbers are [tex]\boxed{12}[/tex] and [tex]\boxed{13}[/tex].
We can then check out work by adding these three numbers together. If they equal [tex]36[/tex], then the answer is correct. [tex]11+12+13=36[/tex]
Add [tex]11[/tex] and [tex]12[/tex]. [tex]23+13=36[/tex]
Add [tex]23[/tex] and [tex]13[/tex]. [tex]36=36[/tex]
This means our answer is correct.