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Speakers A and B are vibrating in phase. They are directly facing each other, are 8.2 m apart, and are each playing a 78.0 Hz tone. The speed of sound is 343 m/s. On the line between the speakers there are three points where constructive interference occurs. What is the distance of the farthest point from speaker A?

Respuesta :

Answer:6.298,4.1,1.9015

Explanation:

Wavelength=[tex]\frac{velocity of sound }{frequency}[/tex]

=[tex]\frac{343}{78}[/tex]=4.397 m

Distance of 3rd speaker from speaker A is x

From B 78-x

Difference between the distances must be a whole number of wavelengths

First

[tex]x-\left ( 8.2-x\right )=4.397[/tex]    for 1 st wavelength

2x=8.2+4.397=12.597

x=6.298m

second

For zero wavelength

[tex]x-\left ( 8.2-x\right )=0[/tex]

2x=8.2

x=4.1m

Third

[tex]\left ( 8.2-x\right )-x=4.397[/tex]

x=1.9015 m

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