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A 300g marble is travelling at a speed of 3.00 m/s horizontally along a tabletop that is 1.00 m above the floor. The marble rolls up a ramp that launches it into the air. At the highest point in its flight the marble has a horizontal velocity of 1.10 m/s. If friction is negligible, how high above the floor is the marble at its highest point?

Respuesta :

gilcarusolautaro

Answer:

The marble at its highest point are hmax= 1.39 meters above the floor.

Explanation:

hi= 1m

V= 3m/s

Vx= 1.1 m/s

Vy= ?

α=cos⁻¹(1.1/3)

α= 68.48º

Vy= V * sin(α)

Vy= 2.79 m/s

Vertical Velocity in highest point are Vy(hmax) = 0

Vy(hmax)= Vy - g*t

t= Vy/g

t= 0.28 sec

t : time to get the highest point

hmax= hi + Vy*t - g*t²/2

hmax= 1.39 m

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