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A radio station claims that the amount of advertising per hour of broadcast time has an average of 10 minutes and a standard deviation equal to 5 minutes. You listen to the radio station for 1 hour, at a randomly selected time, and carefully observe that the amount of advertising time is equal to 8.2 minutes. Calculate the z-score for this amount of advertising time. Round your answer to 2 decimal places.

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JeanaShupp

Answer:   -0.36

Step-by-step explanation:

Given: Mean : [tex]\mu=10\text{ minutes}[/tex]

Standard deviation : [tex]\sigma=5\text{ minutes}[/tex]

We know that the formula to calculate the z-score is given by :-

[tex]z=\dfrac{x-\mu}{\sigma}[/tex]

For x=8.2 minutes, we have

[tex]z=\dfrac{8.2-10}{5}=0.36[/tex]

Hence, the z-score for this amount of advertising time = -0.36

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