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gentlebiker
First evaluate the sq root of 45.
To do so, you have to find perfect square factors (2 x 2, 3 x 3, 4 x 4, and etc.)

The factors of 45 are 3 x 3 x 5.

Notice that there is a 3 x 3. That means you can get the 3 out of the square root and multiply with the number outside of the square root.

11(3)square root 5 - 4 square root 5

33 square root 5 - 4 square root 5

Subtracting and Adding square roots is the same thing as subtracting and Adding variables. If they have the same variable you can +/-. So if they have the same square root, then can +/-.

Answer: 29 square root 5
kudzordzifrancis

Answer:

[tex]29\sqrt{5}[/tex]

Step-by-step explanation:

We want to simplify:

[tex]11\sqrt{45}-4\sqrt{5}[/tex]

We need to simplify the first radical before we can subtract

[tex]11\sqrt{9\times5}-4\sqrt{5}[/tex]

[tex]11\sqrt{9} \times\sqrt{5}-4\sqrt{5}[/tex]

This implies that:

[tex]11\times 3\times\sqrt{5}-4\sqrt{5}[/tex]

[tex]33\sqrt{5}-4\sqrt{5}[/tex]

We have now obtained like surds.

We simplify to get:

[tex]29\sqrt{5}[/tex]

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