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If a nichrome wire has a resistance of 15Ω and is connected across the terminals of a 3.0 V flashlight battery, how much current is in the wire?

1.0 amps
5.0 amps
7.5 amps
0.20 amps

Respuesta :

Answer:

0.20 A

Explanation:

The current in the wire is given by Ohm's law:

[tex]I=\frac{V}{R}[/tex]

where

I is the current

V is the voltage

R is the resistance

In this problem,

V = 3.0 V is the voltage

[tex]R=15 \Omega[/tex] is the resistance

Substituting into the formula,

[tex]I=\frac{3.0 V}{15 \Omega}=0.20 A[/tex]