Answer:
OC) x = -8
Explanation:
Given Equation is:
[tex]y = x^{2} +16x+64[/tex]
Putting y=0 will give us:
[tex]x^{2} +16x+64 = 0[/tex]
The equation is a complete square
The formula is
[tex]a^{2}+2ab+b^{2}=(a+b)^{2}[/tex]
So,
putting in the form of formula
[tex](x)^{2}+ 2.x.8+(8)^{2}=0[/tex]
[tex](x+8)^{2} = 0[/tex]
The square will be cancelled with square root
[tex]\sqrt{(x+8)^{2} } = 0[/tex]
[tex]x+8 = 0[/tex]
[tex]x = -8[/tex]
There is only one root.
So, the solution for x wheny is equal to zero is x = -8 ..
